3(2x^2+2(2-x^2))=2(-4)+20

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Solution for 3(2x^2+2(2-x^2))=2(-4)+20 equation:


Simplifying
3(2x2 + 2(2 + -1x2)) = 2(-4) + 20
3(2x2 + (2 * 2 + -1x2 * 2)) = 2(-4) + 20
3(2x2 + (4 + -2x2)) = 2(-4) + 20

Reorder the terms:
3(4 + 2x2 + -2x2) = 2(-4) + 20

Combine like terms: 2x2 + -2x2 = 0
3(4 + 0) = 2(-4) + 20
3(4) = 2(-4) + 20

Multiply 3 * 4
12 = 2(-4) + 20

Multiply 2 * -4
12 = -8 + 20

Combine like terms: -8 + 20 = 12
12 = 12

Add '-12' to each side of the equation.
12 + -12 = 12 + -12

Combine like terms: 12 + -12 = 0
0 = 12 + -12

Combine like terms: 12 + -12 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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